Calculate what mass of carbon you would need to reduce 15.9g of copper(II) oxide to copper by the reaction:
CuO(s) + C(s) [tex]\rightarrow[/tex] Cu(s) + CO(s)
n = m / ar
(number of moles = mass / relative atomic mass)
If you know any more, it would be really useful for me though ;) .
The Attempt at a Solution
Ar(Cu) = 63.5
Ar(O) = 16.0
Ar(C) = 12.0
CuO = 1 / (63.5 + 16.0) = 79.5g
C = 1 / (12.0) = 12.0g
79.5 / 79.5 * 15.9 = 15.9g of CuO
12.0 / 79.5 * 15.9 = 2.4g of C
Basically, I divided the mass of CuO by the mass of CuO and multiplied by 15.9 to get 15.9g (as in the question). Then, I applied the same equation to C by dividing the mass of C by 79.5 and then multiplying by 15.9 to get 2.4g, which is my answer.
Is this correct?