A single slit is illuminated with a helium-neon laser whose wavelength is 633 nm. If the slit width is 2.2 x 10^-5 m, calculate the third maximum in degrees. Relevant equations: sinO = (m + 1/2)x(wavelength) / w The attempt at a solution: sinO = (m + 1/2)x(wavelength) / w sinO = (3 + 1/2)x(633 x 10^-9 m) / (2.2 x 10^-5 m) O = sin inverse0.100704545 m O = 5.8 degrees The third maximum is approx. 6 degrees. Im not completely sure if this is correct.