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Calculating the Third Maximum

  1. Sep 30, 2009 #1
    A single slit is illuminated with a helium-neon laser whose wavelength is 633 nm. If the slit width is 2.2 x 10^-5 m, calculate the third maximum in degrees.

    Relevant equations:
    sinO = (m + 1/2)x(wavelength) / w

    The attempt at a solution:
    sinO = (m + 1/2)x(wavelength) / w

    sinO = (3 + 1/2)x(633 x 10^-9 m) / (2.2 x 10^-5 m)
    O = sin inverse0.100704545 m
    O = 5.8 degrees

    The third maximum is approx. 6 degrees.

    Im not completely sure if this is correct.
  2. jcsd
  3. Sep 30, 2009 #2
    It's correct. sinO = (m + 1/2)x(wavelength) / w is only approximate anyway. only
    the minima can be calculated exactly with sinO = (m)x(wavelength) / w
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