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- Thread starter mmoadi
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The second part: The field between the plates is 1 V/m, but the field outside the plates isn't

Third part: The E in [itex] E = \frac{1}{2}QV [/itex] is energy, the E in [itex] F = Q E [/itex] is the strength of the electric field, so this calculation is wrong. You need the force per square meter anyway. It's easiest to assume the area of the capacitor is 1 [itex] m^2 [/itex] and then to compute the capacity and the charge and then use [itex] F = Q E [/itex]

Fourth part: wrong for the same reason as third part.

Fifth part: if the voltage is the same, the electric field strength, wich is volt/meter must change

if the distance changes. use V = E * d.

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