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Introductory Physics Homework Help
Calculating useful force or force at an angle
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[QUOTE="gneill, post: 4504550, member: 293536"] Force components sum the way the legs of a right triangle "sum" to find the hypotenuse. As you noted, if the angle is 45° then cos(θ) is 1/√2. But sin(θ) is also 1/√2, so the vertically directed force component is indeed equal to the horizontally directed component. But neither one is half of the net force! For a right triangle with side lengths A and B, the hypotenuse C is given by the relationship: C[SUP]2[/SUP] = A[SUP]2[/SUP] + B[SUP]2[/SUP] Force components add in the same fashion. EDIT: Doc Al beat me to it! [/QUOTE]
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Introductory Physics Homework Help
Calculating useful force or force at an angle
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