1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Calculating vector

  1. Mar 1, 2008 #1
    http://www.users.on.net/~rohanlal/untitl.jpg [Broken]
    In the above diagram how do I calculate a value for theta that makes P's (P is the resultant) vertical component 0?
    Last edited by a moderator: May 3, 2017
  2. jcsd
  3. Mar 1, 2008 #2


    User Avatar
    Staff Emeritus
    Science Advisor

    Is the 120 N vector vertical? Is the magnitude of 80N or the 20° fixed?

    Can one rotate the vectors (triangle) to get P horizontal?
    Last edited: Mar 1, 2008
  4. Mar 1, 2008 #3
    http://users.on.net/~rohanlal/q2-9.jpg [Broken]
    Here is the diagram and question in the text book
    Two forces act on the bracket.
    determine the angle theta that will make the vertical component of the resultant of these two forces zero.

    The bottom force is 175lb and the top one is 145lb
    Last edited by a moderator: May 3, 2017
  5. Mar 1, 2008 #4


    User Avatar
    Science Advisor
    Homework Helper

    (Goodness, what a horrible diagram :yuck: - your 20 degrees looks more like 70 degrees - and is that line supposed to be vertical?)

    If P's vertical component is 0, then P is horizontal.

    So doesn't that make theta 90º?
  6. Mar 1, 2008 #5


    User Avatar
    Science Advisor
    Homework Helper

    one known angle and two known sides

    Ah! Just seen your new diagram (you beat me by a few seconds!)

    ok - now draw a force triangle - it will look nothing like the one in your first post.

    Then you'll have one known angle and two known sides, so you use ordinary trigonometry to find the other angle(s). :smile:
  7. Mar 1, 2008 #6


    User Avatar
    Staff Emeritus
    Science Advisor

    First determine the vertical component of each force.

    Then for the resultant vector to have a zero vertical component, the two vertical force components must be equal in magnitude, but opposite in direction.

    So is the 175 lb force at an angle of 50° and the angle [itex]\theta[/itex] is the angle between the force vectors? If so, then the angle of the 145 lb force with the horizontal is just [itex]\theta[/itex]-50°.
  8. Mar 1, 2008 #7
    I understood Astronuc's method.
    X=67.54 degrees (this is the answer in the back of the txt book)

    Using tim's method the answer was very close (67.6 degrees) but i don't understand how it found the correct answer. I don't understand how using a trig ratio (cosine) automatically found a resultant and angle that had no vertical component.
  9. Mar 2, 2008 #8


    User Avatar
    Science Advisor
    Homework Helper

    Draw a parallelogram!

    Hi Ry!

    Odd isn't it - two apparently different methods giving the same result? :confused:

    To see why they do, draw a parallelogram made of two of the triangles (one a reflection of the other).

    That's two copies of my method!

    Now draw in the perpendiculars to the diagonal from the top and bottom points - you now have two different triangles on the bottom, and a reflection of those same two triangles on the top, with the left and right triangle swapped over - we'll call that Astronuc's parallelogram.

    In my parallelogram, the diagonal represents the third force: you want that force to be horizontal, so you just adjust theta until that diagonal is horizontal.

    In Astronuc's parallelogram, these new perpendicular lines represent the vertical components: you want those components to be equal and opposite, which, after you've made my adjustment, they are.

    Astronuc only uses the two left triangles - but his top left triangle is the same as his bottom right triangle, and his two bottom triangles together are the same as my triangle!

    That's why they give the same result! :smile:

    :smile: Isn't geometry wonderful! :smile:

    (Technically, Astronuc's method is better, because you can use it with more than three forces, but my method has the advantage - especially for me :redface: - that it's more foolproof!)
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Calculating vector
  1. Calculating vectors (Replies: 3)

  2. Vector Calculation (Replies: 0)

  3. Vector Calculation (Replies: 10)

  4. Calculating vectors (Replies: 4)