- #1
suspenc3
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- 0
Hi, I am having a little trouble with this question, I am trying to find the volume of the solid after revolving it.
y=sec x, y=1, x=-1, x=1, about the x-axis
what I did:
[tex]A(x)= \frac{ \pi}{(cosx)^2}[/tex]
and then I integrated from -1 to 1...(my integral came out to [tex]\frac{-1}{sinx}[/tex])
and I got an answer that came out negative..
can anyone help?
y=sec x, y=1, x=-1, x=1, about the x-axis
what I did:
[tex]A(x)= \frac{ \pi}{(cosx)^2}[/tex]
and then I integrated from -1 to 1...(my integral came out to [tex]\frac{-1}{sinx}[/tex])
and I got an answer that came out negative..
can anyone help?