Calculating Work Done in Thermodynamic Problem Q

[Naeem]

Q. A 2-m3 rigid tank contains nitrogen gas at 500kPa and 300 K. Now heat is transferred to the nitrogen in the tank and the pressure of nitrogen rises to 800 kPa. The work done during this process is ...


Do we need to use

W = P2v2 - P1v1/ ( 1-n)

Some guidance requested please.

Thanks,

 

[Q_Goest]

Key words:
"rigid tank" meaning no change in volume. (I'm assuming this says a 2 cubic meter rigid tank.)
"heat transfered" meaning changes in state of the nitrogen are due to heat transfer, not work.

There is no work done, there is only heat transfer changing the state of the nitrogen.

 

[ravenprp]

To calculate the work done in this thermodynamic problem, we can use the formula W = P∆V, where P is the pressure and ∆V is the change in volume. In this case, the initial pressure (P1) is 500 kPa and the final pressure (P2) is 800 kPa. The volume remains constant at 2 m3, so ∆V is 0. Therefore, the work done is 0 kJ.

The formula you mentioned, W = P2v2 - P1v1/ ( 1-n), is used for calculating the work done in a polytropic process, where n is the polytropic index. This formula is not applicable in this scenario as the process is not polytropic.

I hope this helps clarify the calculation of work done in this thermodynamic problem. If you have any further questions, please let me know.