Calculation in C++: B-C && (B-A) /C - Which Answer is Right?

[ccky]

I am doing my homework regarding calculation in c++.
I am confused by the below question.
Int A=2 B=3 C=4
B-C && (B-A) /C
I think the answer is 0 because the first part is negative.
But,my friends say the answer is 1 because -1 not mean false.
I want to ask which answer is right?
Thanks.

 

[Borek]

Your friend is right - -1 doesn't mean false. 0 and only 0 means false.

 

[CompuChip]

You and your friend are both incorrect. You could easily check this by running it through a C++ compiler.

In C++, there is implicit conversion from ints to bools. && has pretty low precedence, so first the following expressions are evaluated: B - C is 3 - 4 = -1, and (B - A) / C is 1 / 4 = 0 (in integer division).
So the resulting expression is -1 && 0 which is equivalent to true && false, hence the result you get is false (0).

 

[Borek]

Ah, I referred just to the small part of the post, I have not actually bothered to evaluate whole expression :shy:

 

[LudusRex]

I would first clarify the question and make sure all variables are defined and the desired outcome is clear. In this case, it seems like the calculation is asking for the result of the expression (B-C && (B-A)/C) where A=2, B=3, and C=4.

In C++, the logical operator && represents "and" and will return a boolean value of true or false. The expression (B-C) evaluates to -1, which is considered true in C++. The second part of the expression (B-A)/C evaluates to 0.25, which is also considered true in C++. Therefore, the overall expression will evaluate to true (1).

However, it is important to note that the answer will vary depending on the programming language and its specific rules for evaluating logical expressions. It is also possible that the question is asking for a different outcome, in which case the answer may be different. It is always important to fully understand the question and its context before providing an answer.