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Calculation of curie constant of iron

  1. Jan 25, 2007 #1
    1. The problem statement, all variables and given/known data
    1)The curie temperature of iron is 1043 Kelvin. Assume that iron atoms, when in metallic form have moments of 2 Bohr magneton per atom. Iron is body centered cube with lattice parameter a = 0.286 nm. Calculate the curie constant.

    2. Relevant equations

    C = [(m^2)(mu)N]/[3K]

    3. The attempt at a solution

    I solved it in the following way:
    Let m be the magnetic moment of an iron atom, let N be the number of atoms per unit volume, let K be the boltzmann constant, let mu be the permeability of free space and let C be the Curie constant.
    m = 2[m(B)] {where m(B) is Bohr magneton}
    = 18.54 x 10^(-24) A-m^2
    N = n/(a^3) {where n is number of atoms in 1 cubic lattice of iron}
    = 2/[(0.286 x 10^(-9))^3]
    = 8.5 x 10^28 atoms per unit volume
    C = [(m^2)(mu)N]/[3K]
    C = 0.89
    But the answer given in my book is 0.66. Please help!
  2. jcsd
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