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I have to make up a 0.5N solution of HNO3 (69%). I have attempted to do the calculation but am not confident if it is correct. Please see below:

no. moles = cv/1000

c = 0.5N v = 100ml

so no.moles = 0.5 x 100/ 1000 = 0.05 moles

mass = 0.05moles/63 = 3.15g

HN03 (69%) = 2.17g

Therefore 2.17g of HNO3 (69%) in 100ml water = 0.5N

Is this correct? (As someone else seems to have got 4.56g as the answer and I dont know where they obtained this from)

Thank you very much for any help.

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# Homework Help: Calculation of molarity - please help

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