Can the Pressure Rise in a System be Calculated When Leakage Changes?

In summary: In the formula's this is not possible since they all work with a fixed pressure difference.I think what you are looking for is the calculation for the pressure rise due to a decrease in leak rate, while keeping the air supply pressure and regulator setting constant. This can be calculated using the continuity equation, which states that the mass flow rate through a system is constant. In this case, the mass flow rate going into the test object (air supply) must be equal to the mass flow rate leaving the test object (leak rate). Since mass flow rate is equal to density times velocity times area, we can rearrange the equation to solve for the velocity at the leak site (since we know the density and area are constant): V =
  • #1
Max de Jong
4
0
Hello,
I am new to this forum but I have a question for you all. It is about the pressure in a system that changes when leakage changes. The test setup has to following components:

- Air supply with 8-10 bar
- Pressure valve that can be manually adjusted
- A flow meter that measures the pressure and the air flow
- A test object with a valve that leaks air

When testing the the manually adjustable pressure regulator is set in such a way that the test object is subjected to 2000 mbar absolute (1000 mbar overpressure). At this pressure the valve always has some leak rate, let's say 10 L/min. If I try to close the valve further with my hands by applying pressure to it so I decrease the leak rate, the pressure before the valve should increase. This is also registered by the flowmeter.

However I would like to know if there is a theoretical way to calculate this pressure rise.

Can anybody give me some advice as to how to tackle this issue?

I know I probably did not give you all the info but I like to learn the approach and than start talking numbers

Hope to hear from one of you.

Regards,

Max de Jong
 
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  • #2
Hello Max, welcome to PF :smile: !

I must be missing something. You have a supply of 2000 mBara to a 'leaky' vessel . If you suppress the leak somewhat, the regulator on the air supply should keep the pressure in the vessel at 2000 mBara, shouldn't it ? And the flowmeter should show a reduced flow to replenish the (now smaller) leak.
 
  • #3
Hello BvU,

Well I am currently graduating as a automotive engineer and I am performing leak tests. As you might know many cars operate with significant boost pressures and any leak will result in a lower pressure inside the intake system of the car.

Hence my question what the theoretical pressure rise would be if I managed to decrease the leak since less energy dissipates through the leak.

The test setup won't correct for the leak since I manually open the air supply to a specific steady state where I reach 2000 mbar absolute and a certain leakage in the test object.

If you have any idea to calculate the pressure rise and want to give an example calculation you can of course assume some values.

If you need more input from me don't hesitate to ask.
 
  • #4
You have pressure dependent leaks. Those leaks have flow rates. You are balancing the leak flows.
The capacity of your system integrates the difference between the leak flow rates.

The pressure regulator is a dynamic system that requires some flow to adjust. When leakage through the regulator exceeds the leakage from the test chamber, the regulator is unable to function. If the test chamber had a bleed that could be adjusted to be greater than the regulator then pressure regulation could be improved.

Maybe you should be using a fixed height water column to regulate your test pressure. A U-tube half full of water will set the test pressure and allow any regulator leakage to escape as bubbles.

We need a diagram of your system before we can be sure what is happening.
 
  • #5
I can't seem to upload a picture so I will try to describe:

air supply ---> Pressure valve (manually operated) ----> Flow and pressure gauge ---> Test object

The test object will be subjected to a certain pressure and will have a certain leak rate when the pressure valve is set to a certain position. I will call this situation 1 and has as pressure of 2000 mbar absolute and a leak rate of 10 L/min

Now for situation 2. There are no smart systems present that compensate for anything. So the air supply stays the same, the pressure valve will remain in the same position as situation 1. The only thing I do is decrease the leak rate. This will increase the pressure before the test object (it shows on the flow and pressure gauge). Let's say this situation will result in a leak rate of 6 L/min and a pressure rise to 2300 mbar absolute.

So I know this is what happens due to my experience with the actual tests but I would like to know how to calculate this pressure rise.

I hope I gave you some answers
 
  • #6
The air supply is assumed to remain a fixed pressure. The manually operated pressure valve is an orifice that presents a resistance to the air flow.

The (air supply pressure) - (the pressure gauge reading) will show the pressure drop across the fixed pressure valve orifice. That pressure drop is a function of flow rate which you adjust by changing the leak rate.You need to investigate the pressure to flow relationship of an orifice.
Take a look at; https://en.wikipedia.org/wiki/Blower_door#Power_law_model_of_airflow
 
  • #7
Hello Baluncore,

If I try and use the theory and formula's on my problem it will also give a pressure drop in the system like all other formula's I've found.
I think it's because they are based on the fact that you can have a certain pressure to create a certain air flow. If you need a lower air flow the pressure has to decrease. This is perfectly logical but it is not what I am looking for.

In reality the pressure rises since you trap more energy (pressure) before the valve which the pressure gauge displays.
 

1. What is pressure rise?

Pressure rise refers to the increase in pressure within a closed system or container. It is typically measured in units of force per unit area, such as pounds per square inch (psi) or pascals (Pa).

2. How is pressure rise calculated?

Pressure rise can be calculated by using the ideal gas law, which states that pressure (P) is equal to the product of the number of moles (n) of gas, the gas constant (R), and the temperature (T) in Kelvin, divided by the volume (V) of the container: P = (nRT)/V. Alternatively, it can also be calculated using the Bernoulli equation, which takes into account fluid flow and changes in velocity.

3. What factors can cause pressure rise?

Pressure rise can be caused by a variety of factors, including an increase in temperature, a decrease in volume, or the presence of a chemical reaction or combustion. In addition, external forces or changes in the environment, such as changes in altitude, can also contribute to pressure rise.

4. How does pressure rise affect systems and materials?

Pressure rise can have significant effects on systems and materials, depending on the magnitude and duration of the pressure increase. In some cases, it can cause structural damage or failure, particularly in materials that are not designed to withstand high pressures. It can also impact the performance and efficiency of systems, such as in engines or pneumatic systems.

5. Are there safety considerations when dealing with pressure rise?

Yes, there are important safety considerations to keep in mind when dealing with pressure rise. It is important to ensure that containers and systems are properly designed and maintained to withstand the expected pressure levels. In addition, safety protocols and equipment should be in place to prevent accidents or injuries due to pressure rise. It is also crucial to follow proper handling and disposal procedures for substances that can cause pressure rise, such as compressed gases or volatile chemicals.

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