1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Calculational Integral

  1. Oct 7, 2007 #1
    1. The problem statement, all variables and given/known data

    [tex]\int\frac{x^3dx}{\sqrt{2-x}}[/tex]




    3. The attempt at a solution
    I solved it in this way
    for v=2-x
    [tex]\int-\frac{(2-v)^3dv}{\sqrt{v}}=-\int\frac{(8-12v+6v^2+v^3)dv}{\sqrt{v}}
    =-\int\frac{8dv}{\sqrt{v}}+\int 12\sqrt{v}dv-\int 6v\sqrt{v}dv-\int v^2\sqrt{v}dv[/tex]
    is it true?
    Is there any other methods?
     
    Last edited: Oct 7, 2007
  2. jcsd
  3. Oct 7, 2007 #2
    That's one way of doing it. If you substitute v2 for 2-x, you will have a radical-free expression to integrate.
     
  4. Oct 7, 2007 #3
    Ok,very nice.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Calculational Integral
  1. Integral calculation (Replies: 2)

  2. Calculate the integral (Replies: 5)

  3. Calculating Integrals (Replies: 2)

  4. Calculate the integrals (Replies: 13)

  5. Integral calculation (Replies: 3)

Loading...