- #1
AymanLak
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Homework Statement
Initial velocity=15m/s slows down to 10m/s in 4.0s. Acceleration= -1.2m/s^2
How far does the car travel in 4.0s
If the car were to slow down at the same rate how much additional distance would it travel before coming to a complete stop
A=d/t
D=(1/2)at^2
I got the acceleration which was the first part of the question and so for the second part (calculating distance traveled in 4.0s) I plugged in the 1.25m/s^2 in the equation d=1/2at^2 and got 2.5m which was marked incorrect. For the third part I have no idea how to solve it
Initial velocity=15m/s slows down to 10m/s in 4.0s. Acceleration= -1.2m/s^2
How far does the car travel in 4.0s
If the car were to slow down at the same rate how much additional distance would it travel before coming to a complete stop
Homework Equations
A=d/t
D=(1/2)at^2
The Attempt at a Solution
I got the acceleration which was the first part of the question and so for the second part (calculating distance traveled in 4.0s) I plugged in the 1.25m/s^2 in the equation d=1/2at^2 and got 2.5m which was marked incorrect. For the third part I have no idea how to solve it