1. The problem statement, all variables and given/known data The temparature T of a liquid at a time t minutes is given by the equation T = 30 + 20e-0.05t, for t > 0 (1)Write down the initial tempatature o the liquid, and find the intial rate of change of temparature. (2)Find the time at which the temparature is 40 2. Relevant equations 3. The attempt at a solution When t=0 the initial temparture is 50. I know that to have to find dT/dt, and i and looked at the answer, which says dT/dt = -0.05 x 20e-0.05t, but i cant see how they got that. what happened to the 30? and how did they get to that point?