- #1
waterchan
- 23
- 0
How would you find the integral of x^3 * ( x^2 - 8 )^1/2 ?
I've tried everything I can think of; substitution / trigonometric substitution, partial fractions, integration by parts, but I just can't get the answer. The answer is supposed to be:
1/15(x^2-8)^3/2 * (3x^2 + 16 )
I've tried everything I can think of; substitution / trigonometric substitution, partial fractions, integration by parts, but I just can't get the answer. The answer is supposed to be:
1/15(x^2-8)^3/2 * (3x^2 + 16 )