How would you find the integral of x^3 * ( x^2 - 8 )^1/2 ?(adsbygoogle = window.adsbygoogle || []).push({});

I've tried everything I can think of; substitution / trigonometric substitution, partial fractions, integration by parts, but I just can't get the answer. The answer is supposed to be:

1/15(x^2-8)^3/2 * (3x^2 + 16 )

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# Calculus 2 Integral

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