- #1

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**Calculus help plz!!!**

Plz help me do the problem below. thanks a lot.

Show that the following integral is CORRECT:

Indefinite Integral of 1/(1-x)^2 dx = x/(1-x)

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- Thread starter gigi9
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- #1

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Plz help me do the problem below. thanks a lot.

Show that the following integral is CORRECT:

Indefinite Integral of 1/(1-x)^2 dx = x/(1-x)

- #2

HallsofIvy

Science Advisor

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because it isn't.

Did you even try differentiating to see if it was correct?

- #3

Hurkyl

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Incidentally, whenever you're doing an indefinite integral, you have to include a constant term; so if this integral is correct, you should write

∫ 1/(1-x)^2 dx = x/(1-x)

(for the record, once you add the "+ C", the answer is correct)

Incidentally, gigi9, how did you come to ask us this question? Does your book say "prove this integral is correct", or did it ask you to find the integral and you derived the RHS on your own?

- #4

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My book say "SHOW THAT THE FOLLOWING INTEGRAL IS CORRECT"

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