y''= -3/(t^3)(adsbygoogle = window.adsbygoogle || []).push({});

s=0 when t = 1

s'= -3/2 when t= (3)^1/2

my answer is....

-3/(2t^-2) - 2t + 7/2

please tell me if that is correct

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# Homework Help: Calculus help

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