- #1
RaptorsFan
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Homework Statement
sin2x / (sin2x + secx) d/dx = ?
Homework Equations
d/dx (f/g) = (g d/dx f - f d/dx g) / g^2
d/dx sec u = sec u tan u d/dx u
d/dx cos u = -sin u d/dx u
d/dx sin u = cos u d/dx u
The Attempt at a Solution
d/dx y= [(sin2x + secx) d/dx (sin2x) - sin2x d/dx (sin2x + secx)] / (sin2x + secx)^2
= [(sin2x + secx) cosx d/dx (2x) - sin2x d/dx (sin2x) + d/dx secx)] / (sin2x + secx)^2
= [(sin2x + secx) cosx (2) - sin2x cos2x (2) + (sec2x*tan2x) 2] / (sin2x + secx)^2
= [2(sin2x + secx) cosx - 2sin2x cos2x + 2(sec2x*tan2x)] / (sin2x + secx)^2
^ That is my final answer, can anyone confirm for me?