# Calculus is false.

1. Jun 6, 2015

### E_Gracka

• OP warned to not post "noise" again
Calculus works for linear equations of the 1st order because it is simple geometry, and that cannot be faulted; one does not need calculus for this. Now take a second order equation, the simple function: y = x^2. From rudimentaries, detay y / deltax = 2x + delta x. That is the EXACT equation for the slope. One can make delta x as small as one wants, however the slope changes. Bringing delta x to infinity, and delta y follows, is the manner in which, all calculations are consistent, but not right. Infinity, as is well known, does not exist, for it is a mathematical trick for some aspects of mathematics to exist. Calculus is a manner in which, to normalise calculations throughout the mathematical and engineering field. Comments please.

2. Jun 6, 2015

### micromass

Staff Emeritus
Are you familiar with epsilon-delta definitions which prove the correctness of the equations?

Are you aware that there is ton of observational evidence for calculus?

3. Jun 6, 2015

### Cruz Martinez

At least you could try to phrase your ideas coherently if you're trying to refute such a successful mathematical theory...

4. Jun 6, 2015

### OldEngr63

Wow, Cruz! That is asking a lot. How can one hope phrase their ideas coherent when doing something fundamentally incoherent? It took a lot of guts for the OP just to put his thoughts up; it is too much to ask that they make sense too!

5. Jun 6, 2015

### phion

In before lock.

6. Jun 6, 2015

7. Jun 6, 2015

### Cruz Martinez

I meant grammatical coherence :D

8. Jun 6, 2015

### Staff: Mentor

It's locked now...

To the OP: A lot of what you wrote was incorrect; in particular, your formulations for $\frac{\Delta y} {\Delta x}$ and your idea that we take $\Delta x$ to $\infty$. Please do some research before making absurd statements about calculus "being false."