I am stuck on a calculus problem.. I have most of the answer but I suddenly got confused, and cant figure it out any further, the question is: The goodfood catering company finds that competitors cater lunch for a group of 100 people for $5 each. The manager of Goodfood calculates the for each 25 cent discount per lunch, its possible to sell an additional 10 lunches. If each lunch costs goodfood $2 to prepare, how many lunches should be prepared to maximize profit. This is what I got so far: let P represent profit, let x represent # of discounted of lunches P=(3-0.25x)(100+10x) =-2.5x^2+5x+300 for the derivative i got x=1. When i substituted that into the above equationi got: =-2.5(1)^2+5(1)+300 =302.5 HERES WHERE I AM LOST!!!! Is this 302.5, the amount of profit they make or is this the number of lunches they should make to make greatest profit.???