# Calculus Prob.

1. Mar 28, 2008

### osqen

1. The problem statement, all variables and given/known data

e^(0,001*a)-((R^2)*(e^(-0,001*a)))

R and a is constant

i cant take ln of this function, pls help

2. Mar 28, 2008

### nicksauce

you can write R^2e^(-0.001a) as e^(ln(R^2)*-0.001a)
can you take it from there?

3. Mar 29, 2008

### sutupidmath

What exactly is your question? I don't see anythig being asked here.

4. Mar 29, 2008

### osqen

my question is x = e^(0,001*a)-((R^2)*(e^(-0,001*a)))

and lnx = ?

5. Mar 29, 2008

### Tom Mattson

Staff Emeritus
I still don't understand what the problem here is. If $x=\exp(0.001a)-R^2\exp(-0.001a)$, then obviously:

$\ln(x)=\ln(\exp(0.001a)-R^2\exp(-0.001a))$.

Am I missing something?

6. Mar 29, 2008

### osqen

i lost my ability :( thank you:)

7. Mar 29, 2008

### HallsofIvy

Staff Emeritus
If you were wondering if it could be simplified at all, the answer is "no".

8. Mar 29, 2008

### osqen

is it the eqn. as simple as it can be