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Calculus Prob.

  1. Mar 28, 2008 #1
    1. The problem statement, all variables and given/known data

    e^(0,001*a)-((R^2)*(e^(-0,001*a)))

    R and a is constant

    i cant take ln of this function, pls help
     
  2. jcsd
  3. Mar 28, 2008 #2

    nicksauce

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    you can write R^2e^(-0.001a) as e^(ln(R^2)*-0.001a)
    can you take it from there?
     
  4. Mar 29, 2008 #3

    What exactly is your question? I don't see anythig being asked here.
     
  5. Mar 29, 2008 #4
    my question is x = e^(0,001*a)-((R^2)*(e^(-0,001*a)))

    and lnx = ?
     
  6. Mar 29, 2008 #5

    Tom Mattson

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    I still don't understand what the problem here is. If [itex]x=\exp(0.001a)-R^2\exp(-0.001a)[/itex], then obviously:

    [itex]\ln(x)=\ln(\exp(0.001a)-R^2\exp(-0.001a))[/itex].

    Am I missing something? :confused:
     
  7. Mar 29, 2008 #6
    i lost my ability :( thank you:)
     
  8. Mar 29, 2008 #7

    HallsofIvy

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    If you were wondering if it could be simplified at all, the answer is "no".
     
  9. Mar 29, 2008 #8
    is it the eqn. as simple as it can be
     
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