Solving e^(0.001a) - (R^2)*(e^(-0.001a)): Help Needed!

[osqen]

Homework Statement

e^(0,001*a)-((R^2)*(e^(-0,001*a)))

R and a is constant

i can't take ln of this function, pls help

 

[nicksauce]

you can write R^2e^(-0.001a) as e^(ln(R^2)*-0.001a)
can you take it from there?

 

[sutupidmath]

Homework Statement

e^(0,001*a)-((R^2)*(e^(-0,001*a)))

R and a is constant

i can't take ln of this function, pls help

What exactly is your question? I don't see anythig being asked here.

 

[osqen]

my question is x = e^(0,001*a)-((R^2)*(e^(-0,001*a)))

and lnx = ?

 

[quantumdude]

I still don't understand what the problem here is. If $x=\exp(0.001a)-R^2\exp(-0.001a)$, then obviously:

$\ln(x)=\ln(\exp(0.001a)-R^2\exp(-0.001a))$.

Am I missing something?

 

[osqen]

i lost my ability :( thank you:)

 

[HallsofIvy]

If you were wondering if it could be simplified at all, the answer is "no".

 

[osqen]

is it the eqn. as simple as it can be