Please help me solve this problem. :yuck:(adsbygoogle = window.adsbygoogle || []).push({});

Find numbers a, b, and c so that the graph of f(x) = ax^2 + bx + c has x-intercepts at (0,0) and (8,0) and a tangent with slope 16 where x = 2.

I have done this so far:

f(x) = ax^2 + bx + c

f '(x) = (2)(a)(x) + b

16 = (2)(a)(2) + b

16 = 4a + b

I don't know where to go from here, so any help would be greatly appreciated.

**Physics Forums - The Fusion of Science and Community**

# Calculus Problem Solving Question

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: Calculus Problem Solving Question

Loading...

**Physics Forums - The Fusion of Science and Community**