Please help me solve this problem. :yuck:(adsbygoogle = window.adsbygoogle || []).push({});

Find numbers a, b, and c so that the graph of f(x) = ax^2 + bx + c has x-intercepts at (0,0) and (8,0) and a tangent with slope 16 where x = 2.

I have done this so far:

f(x) = ax^2 + bx + c

f '(x) = (2)(a)(x) + b

16 = (2)(a)(2) + b

16 = 4a + b

I don't know where to go from here, so any help would be greatly appreciated.

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# Calculus Problem Solving Question

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