Please help me solve this problem. :yuck: Find numbers a, b, and c so that the graph of f(x) = ax^2 + bx + c has x-intercepts at (0,0) and (8,0) and a tangent with slope 16 where x = 2. I have done this so far: f(x) = ax^2 + bx + c f '(x) = (2)(a)(x) + b 16 = (2)(a)(2) + b 16 = 4a + b I don't know where to go from here, so any help would be greatly appreciated.