f(x) = (ax+b)/(x-c) has the following properties(adsbygoogle = window.adsbygoogle || []).push({});

i) the graph of f is symmetric with respect to the y-axis

ii) lim x->2^+ f(x) = + infinite

iii) f^prime (1) = -2

a) Determine the values of a, b and c.

i think c = 2

derivative of f(x) = (-ca - b)/(x-c)^2

so f^prime(1) = -2

-ca-b = (1-c)^2 * -2

if c = 2 then b = -2a + 2

I'm stuck from here. I have no idea how to do this. I tried using this equation

(ax+b)/(x-2) = (-ax + b)/(-x-2)

since symmetric over y axis and i plugged in b, but it turned out to be useless. Please help. thanks

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# Calculus Problem

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