Calculus Question. Using velocity function to find acceleration? The velocity of a falling body is v=8sqrt(s-t)+1 feet per second at the instant t(sec) the body has fallen s feet from its starting point. Show that the body's acceleration is 32 ft/sec^2. Well, the derivative of the velocity function is acceleration, so it's v'=4(v-1)(s-t)^(-1/2) How do I go from there?