- #1

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Solve for y:

x^2 + y^2 + 4x - 6y +12=0

I tried this:

x^2 + 4x + 12 = -y(y-6)

But I don't think that was correct. THe left side wont' factor, and I dont htink that is the right way to approach it.

I also tried to complete the square:

y^2 - 6y = -x^2 - 4x - 12

y^2 - 6y + 9 = -x^2 -4x -12 +9

(y-3)^2 = -x^2 - 4x - 3

But I was not sure how to take the square root of the right side.

Also, this problem was to create an equation whose graph has intercepts at (-5,0), (0,0), and (5,0). I tried a sine graph, but it all seems like guess and check, and I cannot get the intercepts at 5 and -5 exactly.

Thanks so much!