I have a summer calc assignment due tomorrow, and I've been stuck on these two problems. Help is appreciated!!! Solve for y: x^2 + y^2 + 4x - 6y +12=0 I tried this: x^2 + 4x + 12 = -y(y-6) But I don't think that was correct. THe left side wont' factor, and I dont htink that is the right way to approach it. I also tried to complete the square: y^2 - 6y = -x^2 - 4x - 12 y^2 - 6y + 9 = -x^2 -4x -12 +9 (y-3)^2 = -x^2 - 4x - 3 But I was not sure how to take the square root of the right side. Also, this problem was to create an equation whose graph has intercepts at (-5,0), (0,0), and (5,0). I tried a sine graph, but it all seems like guess and check, and I cannot get the intercepts at 5 and -5 exactly. Thanks so much!