- #1

laker_gurl3

- 94

- 0

Take the limit as x approaches infinite...

Square root of 4x^2 + 1 / 2x-3

umm so i really don't know where to start this..i was going to multiply the numerator and denomenator by 1/x, but i don't know what the numerator would be then..

and for number 2.)

Take teh limit as x approaches negative infinite:

3x/square root of x^2 + 6 (i hope you guys know wht i mean by that!)

Anyways for this one i multiplied numerator and denominator by 1/x and got a final answer of 3, but the answer in teh back says -3..i just don't understand that part and where it changes to a negative..

thanks so much guys!