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Calculus troubles yay.

  1. Apr 18, 2006 #1
    Okay, you have 2 equations (and no points on the graph given) -- You have f(x) = 2x-3x^3 and f(x) = c. You are to find the area under the curve between those 2 functions and are to make it equal with the area between the y axis and the 2 curves.

    So, I started this problem initially by creating a graph, and putting all my points on it. I integrated both the areas with respect to x.. and I used (for the area bounded by the y axis and the curves -- which I marked A1) the bounds 0 to 2x-3x^3.

    For the second one, I don't know what bounds to use.. and I think this is where I messed up initially... I used my original bounds which are now clearly wrong...

    I'm so stumped, and it's most likely something silly....

    Edit: in my sleepy stuper, I forgot to include (although it may be obvious) that you are to be solving for C :)
    Last edited: Apr 18, 2006
  2. jcsd
  3. Apr 19, 2006 #2


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    I can't make heads or tails out of what you are saying. To start with you are given y= 2x- 3x3 and y= c and you are asked to find the area between them. Okay, that would be the integral of 2x- 3x3- c where the limits of integration are two points at which the curves intersect (NOT "0 to 2x- 3x3"). Of course for many values of c, those two curves might not intersect twice so there would be no area. I have no idea what you mean by "the area between the y axis and the 2 curves". There is no one region "between the y axis and the 2 curves" so there is no one area.
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