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If x^3 + y^3 - 3xy = 0, dx/dt = -1 , x = 3/2. y = 3/2 what is dy/dr?

So 3x^2 (dx/dt) + 3y^2 (dy/dt) - 3[x(dx/dt) + y(dy/dt)] = 0. So I just substitute values. Is this correct?

Thanks

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# Homework Help: Calculus Verification

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