- #1
ChickenChakuro
- 32
- 0
Hey guys, I'm having difficulty understanding exactly what this problem is asking:
The position vector of an object for [tex]t\geq0[/tex] is [tex]r(t) = <cos(3t),cos(2t)>[/tex].
Find all possible values of [tex]\frac{dy}{dx}[/tex] at the point [tex](0,1/2)[/tex].
Seriously, what does this mean?
The position vector of an object for [tex]t\geq0[/tex] is [tex]r(t) = <cos(3t),cos(2t)>[/tex].
Find all possible values of [tex]\frac{dy}{dx}[/tex] at the point [tex](0,1/2)[/tex].
Seriously, what does this mean?
Last edited: