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Calorimeter help

  1. May 31, 2006 #1
    I needed to know if anyone can help me solve a problem.

    I am supposed to calculate the final temperature after mixing 250 mL of coffee at 80 degrees C with 250 g of ice at 0 degrees C.

    The heat of fusion for ice is 6.01 kJ/mol

    The ice undergoes a phase change, but I don't know how to apply it. Can anyone help me?
  2. jcsd
  3. May 31, 2006 #2


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    Gold Member

    Well the heat of fusion says it all. It is 6.01 kJ/mol. That means that it takes 6.01 kJ of heat to melt 1 mol of ice--that is changing 1 mol of ice at 0 degrees C to 1 mol of water at 0 degrees C.

    Technically you're supposed to show some work before you can get help here, so if you need more help please post to what extent you've worked the problem out so far.
    Last edited: May 31, 2006
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