1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Calorimetry and Water

  1. Nov 21, 2005 #1
    When 42.1 grams of water at 80.9 degrees Celsius are added to an unknown amount of water at 20 degrees Celsius. The final temperature of the mixture is 54.8 degrees Celsius. Calculate the unknown mass of water originally at 20 degrees Celsius.
    For known mass:
    q = (42.1 g)*(54.8-80.9 C)*(4.184 J/g*C) = 4593.0258 J
    Now for unknown mass:
    m = q/C*deltaT
    4593.0258 J/(4.184 J/g*C)*(54.8-20 C) = 31.5448 = 31.5 g???
    Thanks.
     
  2. jcsd
  3. Nov 22, 2005 #2
    Any volunteers?

    Thanks again.
     
  4. Nov 22, 2005 #3

    mezarashi

    User Avatar
    Homework Helper

    (Actually I believe by trying to bump your own threads you lose the chances of a reply - i.e. most people probably look for unreplied threads rather than ones that have been addressed)

    Anyway, going through it, I think your calculations hold.
     
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook




Loading...
Similar Threads for Calorimetry Water Date
Constant-Pressure Calorimetry question Aug 21, 2017
Help with calorimetry Feb 2, 2017
Calorimetry problem Dec 5, 2015
Simple calorimetry problem, melting of water Nov 17, 2012