1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Calorimetry and Water

  1. Nov 21, 2005 #1
    When 42.1 grams of water at 80.9 degrees Celsius are added to an unknown amount of water at 20 degrees Celsius. The final temperature of the mixture is 54.8 degrees Celsius. Calculate the unknown mass of water originally at 20 degrees Celsius.
    For known mass:
    q = (42.1 g)*(54.8-80.9 C)*(4.184 J/g*C) = 4593.0258 J
    Now for unknown mass:
    m = q/C*deltaT
    4593.0258 J/(4.184 J/g*C)*(54.8-20 C) = 31.5448 = 31.5 g???
    Thanks.
     
  2. jcsd
  3. Nov 22, 2005 #2
    Any volunteers?

    Thanks again.
     
  4. Nov 22, 2005 #3

    mezarashi

    User Avatar
    Homework Helper

    (Actually I believe by trying to bump your own threads you lose the chances of a reply - i.e. most people probably look for unreplied threads rather than ones that have been addressed)

    Anyway, going through it, I think your calculations hold.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Calorimetry and Water
  1. Calorimetry & Enthalpy (Replies: 2)

  2. Calorimetry Problem. (Replies: 2)

  3. Calorimetry Problem (Replies: 1)

Loading...