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**1. What is the final temperature when a 3.0 kg gold bar at 99 degrees celsius is dropped into 0.22 kg of water at 25 degrees celsius.**

H20 Heat Capacity (CpH20)= 4186

H20M (mass) = .22 kg

H20Ti (initial temperature) = 25 degrees celsius

Au (CpAu)= 129

AuM (mass) = 3.0 kg

AuTi (initial temperature) = 99 degrees celsius

H20 Heat Capacity (CpH20)= 4186

H20M (mass) = .22 kg

H20Ti (initial temperature) = 25 degrees celsius

Au (CpAu)= 129

AuM (mass) = 3.0 kg

AuTi (initial temperature) = 99 degrees celsius

**2. CpH20 * H20M * ∆TH20 = CpAu * AuM * ∆TAu**

(where ∆T is change in temperature)

(where ∆T is change in temperature)

**3. I *think* Im missing two variables, but Im not sure if I am correct. I am missing the change in temperature for H20, and the final temperature. In order to get either answer, I need another variable. However, I do know that I could get ∆TAu by (Temperature F - Temperature initial), but again, I would need the final temperature.**

Im not sure what I should do in order to find the change in temperature of H20, or maybe Im just reading the problem wrong. I do know that the answer should come out to 47 degrees celsius.

Any advice or help?

Im not sure what I should do in order to find the change in temperature of H20, or maybe Im just reading the problem wrong. I do know that the answer should come out to 47 degrees celsius.

Any advice or help?