# Calorimetry Question

1. Nov 14, 2004

### vg19

Hi,

I have 1 question that I am having trouble with.

1) A stick of molybdenum weighing 237g and starting at a temperature of 373Kelvin is thrust into 244g of water starting at 283Kelvin. If the final Temperature observed for the whole system is 288Kelvin, what would the specific heat of the molybdenum be? Ignore the calorimeter.

For this question I think I am suppose to use the heat lost/gained = mass x C x Temp Change formula and solve for C. However, I am confused on what values to sub in. There are 2 masses, and different temperature.

Any help is much appreciated

Thanks

2. Nov 14, 2004

### CartoonKid

Think like this, the heat lost by molydenum = heat gained by water. $$m_{Mo}C_{Mo}(373-288)=m_{water}C_{water}(288-283)$$. Water's follows water's, Mo's follows Mo's.

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