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Forums
Physics
Special and General Relativity
Can a conformal flat metric be curved?
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[QUOTE="martinbn, post: 6633072, member: 252793"] If you are looking at ##ds^2 = a^2(t)(-dt^2+dx^2+dy^2+dz^2)=-a^2(t)dt^2+a^2(t)dx^2+a^2(t)dy^2+a^2(t)dz^2## you can change the variables ##t'=\int a(t)dt##, the others remain the same, then you get ##-dt'^2+a^2(t')dx^2+a^2(t')dy^2+a^2(t')dz^2## the line element of a typical cosmological solution, which will not be flat unless ##a=const##. Also it is not that hard to caclulate curvature in terms of ##a(t)##. Even if you don't use anything that might simplify the calculations, it will not be so bad. All you need is one component of the Riemann tensor that is not zero, you don't have to compute all. [/QUOTE]
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Physics
Special and General Relativity
Can a conformal flat metric be curved?
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