(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data -

Consider a copper wire 1 mm in diameter providing the power to run an appliance drawing 4.8 kW at 12 V. Assuming no heat radiated away from the wire while the currecnt flows, (a) what will the temperature of the wire be after the current has run for 1 second through the wire? (b) what will the physical condition of the wire be at that time?

2. Relevant equations -

I = P/V

R = V/I

R = pl/A?

I also know the Temperature coefficient of copper is .0068 and its resistivity is 1.68E-8

3. The attempt at a solution -

I solved I = P/V to get 4800 / 12 = 400 A in wire

I also solved R=V/I to get .03 ohms of resistance

At this point I do not know what to do. I am not sure how to turn this info into a heat increase in the wire??? - Thanks very much for any help.

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# Can anyone figure out this electricity problem?

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