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Can anyone help me please?

  1. Sep 7, 2004 #1
    Runner A, who runs with an average speed of 3.0 m/s, starts out at 3:00 P.M. Runner B, who runs with an average speed of 4.0 m/s, starts after A from the same place exactly 5 min later.
    a.) At what time will runner B catch up with runner A?
    b.) If the runners stop when B catches A, how far do they run?
  2. jcsd
  3. Sep 7, 2004 #2


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    We can't help much if we don't know what you can do and where you got stuck.

    Do you know speed= distance/time so that distance = speed* time?

    If you let the time A runs be "t", then the time B runs is "t- 5".

    You know their speeds so using the times above what will be the two distances? Now set them equal and solve for t.
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