Can anyone help me please?

  • Thread starter phywhat
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Runner A, who runs with an average speed of 3.0 m/s, starts out at 3:00 P.M. Runner B, who runs with an average speed of 4.0 m/s, starts after A from the same place exactly 5 min later.
a.) At what time will runner B catch up with runner A?
b.) If the runners stop when B catches A, how far do they run?
 

Answers and Replies

  • #2
HallsofIvy
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We can't help much if we don't know what you can do and where you got stuck.

Do you know speed= distance/time so that distance = speed* time?

If you let the time A runs be "t", then the time B runs is "t- 5".

You know their speeds so using the times above what will be the two distances? Now set them equal and solve for t.
 

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