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Can anyone show me this?

  1. May 30, 2007 #1
    http://ejokeimg.pchome.com.tw/see-post.html?Flow_No=30201&cat=47&rank=" [Broken]

    I try using the commutation relation of the position operator and the Hamiltonian, but failed.:bugeye::bugeye:

    Thanks for your kindly help!
    Last edited by a moderator: May 2, 2017
  2. jcsd
  3. May 30, 2007 #2
    By the way, I don't know how to show the pics directly, sorry about that.
  4. May 30, 2007 #3
    Multiply the left hand side by the energy denominator. Insert the hamiltonian operator. The commutator trick should then work.
  5. May 30, 2007 #4

    Thanks for your reply.^^ You mean like this?
    But it's not the original equation. I know that the commutator of position and Hamiltonian is equal to velocity multiplies by
    i and hbar(positive or negative sign added). But what I wanna know is how to transform the position operator "itself" into the "velocity form" in the first pic I posted. Or my procedure is simply incorrect?

    Attached Files:

    Last edited: May 30, 2007
  6. May 31, 2007 #5
    Ooooooooooops, I got through it, thanks for you help!!
    You are right! No further questions at all...
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