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Can I factor it?

  1. Jul 2, 2005 #1
    On my process of obtaining the IF for solving a differential equation, I got stuck with an equation as following. This could be a very simple algebra problem, but I just can't do it. Would someone tell me if I can factor the numerators by (x^4 + 1) for the first equation and by (x^4 -1) for the second equation so that I can have only x or y as a variable?

    [(x^4 - 1) - (5*x^4 + 1)]/x*(x^4+1) = (-4*x^4 - 2)/x(x^4 + 1)
    = -2(2*x^4 +1)/x(x^4 + 1)

    [(5*x^4 + 1) - (x^4 - 1)]/y*(x^4-1) = (4x^4 + 2)/y(x^4 - 1)
    =2(2*x^4 + 1)/y(x^4 - 1)

    Thanks for your help in advance.
     
  2. jcsd
  3. Jul 2, 2005 #2
    could you use [tex]\LaTeX[/tex] please. it is kinda hard to read without it.
     
  4. Jul 2, 2005 #3
    OK, I got it. Please take look at the following.

    [([tex]x^4[/tex] - 1) - (5[tex]x^4 [/tex]+ 1)]/x([tex]x^4[/tex]+1) = (-4[tex]x^4[/tex] - 2)/x([tex]x^4[/tex] + 1)
    = -2(2[tex]x^4[/tex] +1)/x([tex]x^4[/tex]+ 1)

    [(5[tex]x^4[/tex] + 1) - ([tex]x^4[/tex] - 1)]/y([tex]x^4[/tex]-1) = (4[tex]x^4[/tex] + 2)/y([tex]x^4 [/tex]- 1)
    =2(2[tex]x^4 [/tex]+ 1)/y([tex]x^4[/tex] - 1)

    Thanks for your suggestion. I always wanted to know how to type [tex]x^2[/tex] for x^2.
     
    Last edited: Jul 2, 2005
  5. Jul 2, 2005 #4
    ur kidding, right? one exponent isn't enough(especially without the x :smile:)
     
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