Can i get some one to do this probfor me

  • Thread starter bigskilly
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In summary, the conversation is about finding the volume of a solid with a base bounded by y = (x^2)-2 and y=4, filled with squares perpendicular to the x-axis. The length of a side of the squares is determined by the equation s = 4 - [(x^2)-2]. The volume of a slice of the solid can be calculated using dV = s^2dx. To find the total volume, the limits for x must be determined and then integrated.
  • #1
bigskilly
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Find the volume of the solid formed with a base bounded by y = (x^2)-2 and y=4 filled with squares that are perpendicualr to the x-axis.
 
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  • #2
If your speaking of volume, what are the limits on the z-axis
 
  • #3
bigskilly said:
Find the volume of the solid formed with a base bounded by y = (x^2)-2 and y=4 filled with squares that are perpendicualr to the x-axis.

One side of each square lies in the x-y plane. The length of a side is s = 4 - [(x^2)-2]. The volume of a slice of the solid is dV = s^2dx. Figure out the limits for x (where the two boundry lines cross, and integrate.
 

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