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Antonio Lao
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Can Quantum Jumps Same as Dimension Jumps ?
By going back to Bohr's stationary orbits of electrons, The idea of quantum jumps was born.
We can hypothesize that matter such as electrons are 4D objects and photons are 3D objects and the continuous space between orbits is a 2D continuum. So what happens when one electron jumps from one orbits to another orbit is that the 4D electron transforms to 3D energy and the 3D energy transforms to a 2D continuum then 2D continuum back to 3D energy and then back to a 4D electron at a lower or higher orbit whichever the case in question. And transformation of 2D continuous space (S) is given by:
[tex] S = cE [/tex]
where c is the speed of light in vacuum and it acts as dimension lowering constant for energy (E).
And by dimensional analysis, the 2D continuous space is proportional to an arbitrary surface area with the proportionality constant as force per unit of time. Futhermore force per unit time is proportional to the time derivative of acceleration with mass as the constant of proportionality.
[tex] \frac {Force}{time} = m \frac {\partial a}{\partial t}[/tex]
By going back to Bohr's stationary orbits of electrons, The idea of quantum jumps was born.
We can hypothesize that matter such as electrons are 4D objects and photons are 3D objects and the continuous space between orbits is a 2D continuum. So what happens when one electron jumps from one orbits to another orbit is that the 4D electron transforms to 3D energy and the 3D energy transforms to a 2D continuum then 2D continuum back to 3D energy and then back to a 4D electron at a lower or higher orbit whichever the case in question. And transformation of 2D continuous space (S) is given by:
[tex] S = cE [/tex]
where c is the speed of light in vacuum and it acts as dimension lowering constant for energy (E).
And by dimensional analysis, the 2D continuous space is proportional to an arbitrary surface area with the proportionality constant as force per unit of time. Futhermore force per unit time is proportional to the time derivative of acceleration with mass as the constant of proportionality.
[tex] \frac {Force}{time} = m \frac {\partial a}{\partial t}[/tex]
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