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Can some verify this problem?

  1. Oct 23, 2007 #1
    1. The problem statement, all variables and given/known data
    The problem has to do with laws of cosines/sines.

    "The baseball player in center field is playing approximately 330 feet from the television camera that is behind home plate. A batter hits a fly ball that goes to the wall 420 feet from the camera. The camera turns 6 degrees to follow the play. Approximate the distance the center field has to run to make the catch."

    The diagram given looks roughly like this:
    [​IMG]

    2. Relevant equations

    There are 3 equations relating to the Laws of Cosines:

    1. a^2 = b^2 + c^2 - 2bccos(A)
    2. b^2 = a^2 + c^2 - 2accos(B)
    3. c^2 = a^2 + b^2 - 2abcos(C)


    3. The attempt at a solution

    At this point the case of this problem is SAS (side side angle). So I know that laws of cosines has to be used here.

    I then labeled the diagram like this:
    [​IMG]

    Givens:
    b=420
    c=330
    A=6 degrees
    a = ?

    a is what needs to be solved.

    I then used equation one since it has the most related givens

    a^2 = b^2 + c^2 - 2bccos(A)
    a^2 = 420^2 + 330^2 - 2(420)(330)cos6

    a = [tex]\sqrt{420^2 + 330^2 - 2(420)(330)cos6}[/tex]

    a = 98.07ft

    Thats my approximate answer. Can someone verify it?
     
  2. jcsd
  3. Oct 23, 2007 #2

    EnumaElish

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    Science Advisor
    Homework Helper

    The expression in the root is correct.
     
  4. Oct 28, 2007 #3
    So is everything correct?
     
  5. Oct 28, 2007 #4
    Since you are taking the root of a number it should be +-. But negative distance doesn't make sense, but it is something to keep in mind.
     
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