# Homework Help: Can somebody check my conversion

1. Jul 20, 2009

### physics10189

1. The problem statement, all variables and given/known data

Well, I am not sure about my conversion and I need people to make sure I am doing it right.

I have a period, T, of 17.29 ms. To find the frquency it is 1/T= 57.836 s^-1. So the inductive is L=((1/(2*pi*frequency))^2)/C which C is 110*10^-6 and I got L=68.84 mh.

The lower case m are 10^-3 btw.

Can anyone make sure I did this right and the conversion....thanks!!!

2. Relevant equations

3. The attempt at a solution

2. Jul 20, 2009

### rock.freak667

Re: Conversion

I am not sure of this anymore but isn't the impedence of a capacitor = 1/(2*pi*f*C) ?

3. Jul 20, 2009

### physics10189

Re: Conversion

Well it doesn't matter if C is something or L is something...I just want to know what is L with the given values, more of plug and chug situation. I just want to know if I made my conversion right with the given equation.

4. Jul 20, 2009

### rock.freak667

Re: Conversion

well in that case, your conversion is correct.

5. Jul 20, 2009

### physics10189

Re: Conversion

Ok thanks then.