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Can somebody check my conversion

  1. Jul 20, 2009 #1
    1. The problem statement, all variables and given/known data

    Well, I am not sure about my conversion and I need people to make sure I am doing it right.

    I have a period, T, of 17.29 ms. To find the frquency it is 1/T= 57.836 s^-1. So the inductive is L=((1/(2*pi*frequency))^2)/C which C is 110*10^-6 and I got L=68.84 mh.

    The lower case m are 10^-3 btw.

    Can anyone make sure I did this right and the conversion....thanks!!!

    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Jul 20, 2009 #2

    rock.freak667

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    Re: Conversion

    I am not sure of this anymore but isn't the impedence of a capacitor = 1/(2*pi*f*C) ?
     
  4. Jul 20, 2009 #3
    Re: Conversion

    Well it doesn't matter if C is something or L is something...I just want to know what is L with the given values, more of plug and chug situation. I just want to know if I made my conversion right with the given equation.
     
  5. Jul 20, 2009 #4

    rock.freak667

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    Re: Conversion

    well in that case, your conversion is correct.
     
  6. Jul 20, 2009 #5
    Re: Conversion

    Ok thanks then.
     
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