1. The problem statement, all variables and given/known data A manometer is attached to a pipe on end and open on the other. The manometer fluid is n-heptane while the process fluid is nitrogen gas. If the height difference between the two is 680 mm what is the pressure of the fluid in the pipe? 2. Relevant equations P1-P2 = density of manometer fluid*g*h <---since process fluid is a gas 3. The attempt at a solution I figured that you would be solving for P1 and so I did P1-1 atm=9.8N/kg x 684 kg/m^3 (this is the density of n-heptane) x .680 m x 1 atm/1.01325x 10^5 = .045 atm P1=1 atm+.045 atm = 1.045 atm I'd really appreciate if someone could help me on this. Thanks!