# Can someone check?

1. Jan 27, 2005

### Erin_Sharpe

(3^5/3^3)^2
= 3^2+2
=3^4
= 81

3log6-log612 + log62=
log68

Appreciate it if someone could tell me if i'm right or not.

Thanks,
Erin

2. Jan 27, 2005

### hypermorphism

You got the first one right.
In the second one, do you mean log63 ?

3. Jan 27, 2005

### Erin_Sharpe

how did u get the second answer...? because i really did get log68

4. Jan 27, 2005

### Gonzolo

He is asking to rewrite your second problem correctly. What does the 6 mean in the first term?

5. Jan 27, 2005

### Erin_Sharpe

oh i see now. but, no i dont mean log63...its written in the text exactly the way I wrote it.

6. Jan 27, 2005

### arildno

Erin sharpe:
You HAVE to use a less ambiguous notation!!
Do you mean:
a) $$3log_{6}$$
b) $$3log(6)$$

And do you mean:
c) $$log_{6}(12)$$
Or
d)$$log(612)$$