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Can someone check?

  1. Jan 27, 2005 #1
    (3^5/3^3)^2
    = 3^2+2
    =3^4
    = 81

    3log6-log612 + log62=
    log68

    as a final answer?

    Appreciate it if someone could tell me if i'm right or not.

    Thanks,
    Erin
     
  2. jcsd
  3. Jan 27, 2005 #2
    You got the first one right.
    In the second one, do you mean log63 ?
     
  4. Jan 27, 2005 #3
    how did u get the second answer...? because i really did get log68
     
  5. Jan 27, 2005 #4
    He is asking to rewrite your second problem correctly. What does the 6 mean in the first term?
     
  6. Jan 27, 2005 #5
    oh i see now. but, no i dont mean log63...its written in the text exactly the way I wrote it.
     
  7. Jan 27, 2005 #6

    arildno

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    Erin sharpe:
    You HAVE to use a less ambiguous notation!!
    Do you mean:
    a) [tex]3log_{6}[/tex]
    b) [tex]3log(6)[/tex]

    And do you mean:
    c) [tex]log_{6}(12)[/tex]
    Or
    d)[tex]log(612)[/tex]
     
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