For function f(x)=1/(1+x^2), calculate Taylor polynomials for the 2nd and 4th degree about the point a=0.(adsbygoogle = window.adsbygoogle || []).push({});

The answer was:

P2 = 1-x^2;

P4 = 1-x^2+x.^4

for 2nd degree I got -2x/[(1+x^2)^2]

for 4th degree I got 12x/[(1+x^2)^4]

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# Can someone explain this?(Taylor polynomials)

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