Can someone help me with relative motion

[hockeynicole]

Homework Statement

if a car 1 is traveling north at 13m/s
and another car (2) is driving 20 degrees north of west at 7.0m/s

1.What is the velocity of car 1 relative to car 2
2.What is the velocity of car 2 relative to car 1?

i don't understand how to solve this? could someone help, are the relative velocities different?

Homework Equations

The Attempt at a Solution

My attempt...

components of car 2
sin 20 = op/hyp = op/7
y=2.39 North

cos20=x/7
x=6.58 West

then i don't know what to do

 

[Hootenanny]

Homework Statement

if a car 1 is traveling north at 13m/s
and another car (2) is driving 20 degrees north of west at 7.0m/s

1.What is the velocity of car 1 relative to car 2
2.What is the velocity of car 2 relative to car 1?

i don't understand how to solve this? could someone help, are the relative velocities different?

Of course we can help you solve the question, but we won't do it for you. You need to show some effort in solving the question yourself before we can help you.

 

[baba89]

Sure, I can help you with relative motion. Relative motion is the study of how the motion of one object appears to another object that is observing it. In this case, we have two cars, car 1 and car 2, and we want to find the relative velocity between them.

To solve this problem, we first need to define the reference frame. In this case, let's take car 1 as our reference frame. This means that we will be observing the motion of car 2 from the perspective of car 1.

1. To find the velocity of car 1 relative to car 2, we need to subtract the velocity of car 2 from the velocity of car 1. Since car 1 is traveling north at 13m/s, its velocity can be represented as (0,13) where the first number represents the velocity in the x-direction and the second number represents the velocity in the y-direction. Similarly, car 2 is traveling 20 degrees north of west at 7.0m/s, so its velocity can be represented as (-6.58,2.39) where the first number represents the velocity in the x-direction and the second number represents the velocity in the y-direction. Now, to find the relative velocity of car 1 with respect to car 2, we simply subtract the components of car 2 from car 1: (0-(-6.58), 13-2.39) = (6.58, 10.61). Therefore, the relative velocity of car 1 with respect to car 2 is 6.58m/s west and 10.61m/s north.

2. To find the velocity of car 2 relative to car 1, we need to subtract the velocity of car 1 from the velocity of car 2. Since car 2 is traveling at (-6.58,2.39)m/s and car 1 is traveling at (0,13)m/s, the relative velocity of car 2 with respect to car 1 is (-6.58-0, 2.39-13) = (-6.58, -10.61). This means that from the perspective of car 1, car 2 is moving at a velocity of 6.58m/s west and 10.61m/s south.

I hope this helps you understand relative motion better. Remember, the relative velocities will be different