1. Feb 7, 2005 #1

   Bossieman

   

   sum (sin(nx)/n)
   where n goes from 1 to infinity.
   The result should be (1/2)*(pi-x) when 0(x(pi
   and -(1/2)*(pi+x) when -pi(x(0
   
   I need someone to show me how to attack this problem.
   Thanks

    

   Bossieman, Feb 7, 2005
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3. Feb 8, 2005 #2

   TenaliRaman

   

   sin(nx)/n = RE[e^inx/n]
   (Further Hint : log series)
   
   -- AI

    

   TenaliRaman, Feb 8, 2005
4. Feb 8, 2005 #3

   mathman

   

   Science Advisor

   Correction to TenaliRaman. sin is imaginary part, cos is real part.

    

   mathman, Feb 8, 2005
5. Feb 8, 2005 #4

   mathwonk

   

   Science Advisor

   Homework Helper

   I would try computing the fourier coefficents of x.

    

   mathwonk, Feb 8, 2005
6. Feb 9, 2005 #5

   TenaliRaman

   

   OOPS!
   
   -- AI

    

   TenaliRaman, Feb 9, 2005

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