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Can someone please explain how to solve this IVP?

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  1. Oct 22, 2015 #1
    • Missing homework template due to originally being posted in other forum
    x' =-5x-y
    y' =4x-y

    I got
    x=ae^-3t+bte^-3t
    y=-2bte^-3t+2ae^-3t+be^-3t
    a=0 b=0

    The answer is
    x=e^(-3t+3)-te^(-3+3)
    y=-e^(-3+t)+2te^(-3+3)
    I dont understand where the +3 comes from
     
  2. jcsd
  3. Oct 22, 2015 #2

    Geofleur

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    What are the initial conditions on x and y?
     
  4. Oct 24, 2015 #3

    HallsofIvy

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    [itex]e^{-3t+ 3}= (e^3)e^{-3t}[/itex]. The "+ 3" just gives a specific value to your constant "a".
     
  5. Oct 24, 2015 #4

    Ray Vickson

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    This is not an IVP, because you have not given any initial values. That is what the "IV" stands for.
     
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