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Can someone please explain the steps for me:

  1. Oct 14, 2005 #1
    How can you go from:

    (1+x)^(k-1) / (1+x)^(2k)
    to:
    1/ (1+x)^(k+1)

    ?

    Thanks!
     
  2. jcsd
  3. Oct 14, 2005 #2

    VietDao29

    User Avatar
    Homework Helper

    You can use:
    [tex]\frac{a ^ \alpha}{a ^ \beta} = a ^ {\alpha - \beta}[/tex]
    And [tex]a ^ {- \alpha} = a ^ {0 - \alpha} = \frac{a ^ 0}{a ^ \alpha} = \frac{1}{a ^ \alpha}[/tex] to solve the problem. So:
    [tex]\frac{(1 + x) ^ {k - 1}}{(1 + x) ^ {2k}} = (1 + x) ^ {k - 1 - 2k} = ...[/tex]
    Can you go from here?
    Viet Dao,
     
  4. Oct 14, 2005 #3
    = (1+x)^(-k-1)
    =1 / (1+x)^(k+1)

    Right?
     
  5. Oct 14, 2005 #4

    VietDao29

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    Homework Helper

    Yup. That's correct. :smile:
    Viet Dao,
     
  6. Oct 14, 2005 #5
    Ok, thanks :)
     
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